Science
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Chapter 12: Electricity
Class: X
Exercise 4
Question 1
Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 5 Ω resistor, an 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series.
Answer 1
Circuit diagram:
Question 2
Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?
Answer 2
Circuit diagram with ammeter to measure current and voltmeter across the 12W resistor:
Given,
Resisters are connected in series, the net resistance in the circuit = 5 Ω + 8 Ω + 12 Ω = 25 Ω
Net potential = 6 V
Using Ohm’s law, V = IR
For voltmeter, R= 12 Ω resistor, current = 0.24 A
V = 0.24 × 12 V = 2.88 V
Therefore, the reading in the ammeter is 0.24 and voltmeter is 2.88.
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