Chapter 12: Electricity- Exercise- 4

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Chapter 12: Electricity

Class: X

Exercise 4

 

Question 1

Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 5 Ω resistor, an 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series.

Answer 1

Circuit diagram:

 

Question 2

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

Answer 2

Circuit diagram with ammeter to measure current and voltmeter across the 12W resistor:

 

Given,

Resisters are connected in series, the net resistance in the circuit = 5 Ω + 8 Ω + 12 Ω = 25 Ω

Net potential = 6 V

Using Ohm’s law, V = IR

For voltmeter, R= 12 Ω resistor, current = 0.24 A

V = 0.24 × 12 V = 2.88 V

Therefore, the reading in the ammeter is 0.24 and voltmeter is 2.88.